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Calculus

Unit 4

Differentiation Rules

6 topics · 24 practice questions · Free responseNot yet reviewed

Notes

Basic rules

  • Power rule: $(x^n)' = nx^{n-1}$. Constant multiple and sum rules let you differentiate term by term. The derivative of a constant is 0.
  • Product rule: $(fg)' = f'g + fg'$.
  • Quotient rule: $\displaystyle \left(\frac{f}{g}\right)' = \frac{f'g - fg'}{g^2}$.

Chain rule

  • $[f(g(x))]' = f'(g(x))\,g'(x)$: differentiate the outside, then multiply by the derivative of the inside.

Special functions

  • $(\sin x)' = \cos x$, $(\cos x)' = -\sin x$, $(\tan x)' = \sec^2 x$.
  • $(e^x)' = e^x$, $\displaystyle (\ln x)' = \frac{1}{x}$, $(a^x)' = a^x \ln a$.
  • Chain versions: $(e^u)' = e^u u'$, $\displaystyle (\ln u)' = \frac{u'}{u}$, $(\sin u)' = u'\cos u$.

Topics in this unit

Each topic has its own short notes and practice.

Practice

Find $\displaystyle \frac{d}{dx}[5x^4 - 3x + 2]$.
Find $\displaystyle \frac{d}{dx}[x^2 \sin x]$.
Find $\displaystyle \frac{d}{dx}\left[\frac{e^x}{x}\right]$.
Find $\displaystyle \frac{d}{dx}[\cos(5x)]$.
Find $\displaystyle \frac{d}{dx}[\ln(x^2 + 1)]$.
What is the slope of $y = (x^2 + 1)^3$ at $x = 1$?

Free response

Write your answer first, then open the scoring guide.

Free-response question

Let $g(x) = x^3 \sin x$, $h(x) = (2x + 1)^4$ and $k(x) = \frac{x}{x^2 + 1}$.

(a) Find $g'(x)$.

Show the answer and scoring guide

Product rule: $g'(x) = 3x^2 \sin x + x^3 \cos x$.

Check off the points you earned:

(b) Find $h'(x)$.

Show the answer and scoring guide

Chain rule: $h'(x) = 4(2x + 1)^3 \cdot 2 = 8(2x + 1)^3$.

Check off the points you earned:

(c) Find $k'(x)$ and show that $k$ has a horizontal tangent at $x = 1$.

Show the answer and scoring guide

Quotient rule: $\displaystyle k'(x) = \frac{(1)(x^2 + 1) - x(2x)}{(x^2 + 1)^2} = \frac{1 - x^2}{(x^2 + 1)^2}$. At $x = 1$ the numerator is 0, so $k'(1) = 0$ and the tangent is horizontal.

Check off the points you earned: