Integrated Math 3 / Unit 5: Trigonometric Functions
5.2 The Unit Circle
Notes
The unit circle has radius 1 and center at the origin. The point at angle $\theta$ is $(\cos\theta, \sin\theta)$.
- Key values: $\displaystyle \sin\frac{\pi}{6} = \frac{1}{2}$, $\displaystyle \cos\frac{\pi}{6} = \frac{\sqrt{3}}{2}$; $\displaystyle \sin\frac{\pi}{4} = \cos\frac{\pi}{4} = \frac{\sqrt{2}}{2}$; $\displaystyle \sin\frac{\pi}{3} = \frac{\sqrt{3}}{2}$, $\displaystyle \cos\frac{\pi}{3} = \frac{1}{2}$.
- Use the reference angle and the quadrant signs. Sine is positive in quadrants I and II. Cosine is positive in I and IV.
- Axes: $\cos\pi = -1$, $\displaystyle \sin\frac{3\pi}{2} = -1$, $\cos 0 = 1$.
- Since the point is on the circle, $\cos^2\theta + \sin^2\theta = 1$.
Practice
What is $\displaystyle \sin\frac{5\pi}{6}$?
The reference angle is $\displaystyle \frac{\pi}{6}$ and sine is positive in quadrant II.
What is $\displaystyle \cos\frac{4\pi}{3}$?
$\displaystyle \frac{4\pi}{3}$ is in quadrant III with reference angle $\displaystyle \frac{\pi}{3}$. Cosine is negative there.
An angle $\theta$ is in quadrant II and $\displaystyle \sin\theta = \frac{3}{5}$. What is $\cos\theta$?
$\displaystyle \cos^2\theta = 1 - \frac{9}{25} = \frac{16}{25}$, and cosine is negative in quadrant II.
Ready for more? Take the Unit 5 test.