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Trigonometry / Unit 6: Trigonometric Identities

6.6 Half-Angle Formulas

3 practice questionsNot yet reviewed

Notes

Solving the double-angle formula for the half angle gives:

  • $\displaystyle \sin\frac{\theta}{2} = \pm\sqrt{\frac{1 - \cos\theta}{2}}$ and $\displaystyle \cos\frac{\theta}{2} = \pm\sqrt{\frac{1 + \cos\theta}{2}}$.
  • $\displaystyle \tan\frac{\theta}{2} = \frac{\sin\theta}{1 + \cos\theta} = \frac{1 - \cos\theta}{\sin\theta}$.
  • Choose the sign from the quadrant of $\displaystyle \frac{\theta}{2}$, not of $\theta$.
  • Example: $\displaystyle \cos 15^\circ = \sqrt{\frac{1 + \cos 30^\circ}{2}} = \sqrt{\frac{2 + \sqrt{3}}{4}} = \frac{\sqrt{2 + \sqrt{3}}}{2}$.

Practice

What is the exact value of $\cos 15^\circ$?
What is the exact value of $\sin 22.5^\circ$?
To find $\displaystyle \cos\frac{\theta}{2}$ when $\theta = 300^\circ$, which sign does the half-angle formula take?

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