AP Calculus BC / Unit 3: Differentiation: Composite, Implicit, and Inverse Functions

3.4 Differentiating Inverse Trigonometric Functions

3 practice questions

Notes

$\displaystyle \frac{d}{dx}\arcsin x=\frac{1}{\sqrt{1-x^2}}$
$\displaystyle \frac{d}{dx}\arccos x=-\frac{1}{\sqrt{1-x^2}}$
$\displaystyle \frac{d}{dx}\arctan x=\frac{1}{1+x^2}$
Use the chain rule for inside functions.

Practice

$\displaystyle \frac{d}{dx}\arctan x$ at $x=1$ equals:

$\displaystyle \frac{d}{dx}\arcsin(2x)=$

Which derivative is negative?

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