AP Physics 2 / Unit 11: Electric Circuits
11.4 Electric Power
Notes
$$P=IV=I^2R=\frac{V^2}{R}$$
Practice
A 120 V device draws 2 A. Power:
$IV$.
A 10 Ω resistor carries 3 A. Power:
$I^2R$.
Which bulb is brighter on the same voltage?
$\displaystyle P=\frac{V^2}{R}$.
Ready for more? Take the Unit 11 test.