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Integrated Math 3

Unit 4

Radical Functions and Equations

6 topics · 24 practice questions · Free responseNot yet reviewed

Notes

Roots and exponents

  • $\displaystyle \sqrt[n]{a} = a^{1/n}$ and $\displaystyle a^{m/n} = (\sqrt[n]{a})^m$. Negative exponents give reciprocals.
  • Simplify radicals by factoring out perfect powers: $\displaystyle \sqrt{72} = 6\sqrt{2}$.

Radical functions

  • $\displaystyle f(x) = a\sqrt{x - h} + k$ starts at $(h, k)$. Its domain is $x \geq h$. A negative $a$ reflects it over the $x$-axis.
  • $\displaystyle g(x) = a\sqrt[3]{x - h} + k$ is centered at $(h, k)$ and has domain and range of all real numbers.

Solving radical equations

  • Isolate the radical, raise both sides to the matching power, solve, then check.
  • Squaring can create extraneous solutions, so always substitute back into the original equation. A square root can never equal a negative number.

Topics in this unit

Each topic has its own short notes and practice.

Practice

Evaluate $32^{3/5}$.
What is the domain of $\displaystyle f(x) = \sqrt{5 - x}$?
Solve $\displaystyle \sqrt{2x + 1} = 7$.
Solve $\displaystyle x + 1 = \sqrt{x + 3}$.
Which statement about $\displaystyle f(x) = -\sqrt[3]{x - 3} + 4$ is true?
A pendulum has period $\displaystyle T = 2\pi\sqrt{\frac{L}{9.8}}$ with $L$ in meters. Which length gives a period of $2\pi$ seconds?

Free response

Write your answer first, then open the scoring guide.

Free-response question

The distance to the horizon from a height of $h$ feet is modeled by $d = \sqrt{1.5h}$ miles.

(a) How far can a person see from the top of a 150 foot tower?

Show the answer and scoring guide

$\displaystyle d = \sqrt{1.5 \cdot 150} = \sqrt{225} = 15$ miles.

Check off the points you earned:

(b) How high must an observer be to see 12 miles to the horizon?

Show the answer and scoring guide

$\displaystyle 12 = \sqrt{1.5h} \Rightarrow 144 = 1.5h \Rightarrow h = 96$ feet.

Check off the points you earned:

(c) Does doubling the height double the distance? Use $h = 96$ and $h = 192$ to explain.

Show the answer and scoring guide

At $h = 96$, $d = 12$. At $h = 192$, $\displaystyle d = \sqrt{288} \approx 16.97$, about 17 miles. This is only about $1.41$ times as far, not 2 times, because $d$ grows with the square root of $h$.

Check off the points you earned: