Notes
Endothermic and exothermic
- Exothermic: releases heat to the surroundings; $\Delta H < 0$; the surroundings get warmer.
- Endothermic: absorbs heat; $\Delta H > 0$; the surroundings get colder.
- Energy diagrams: products lower than reactants means exothermic.
- Thermal equilibrium: heat flows from hot to cold until temperatures match. The heat lost by one object equals the heat gained by the other.
Calorimetry
$q = mc\Delta T$, where $c$ is specific heat (water: 4.18 J/g·°C).
- In a coffee-cup calorimeter, $q_{reaction} = -q_{solution}$.
- $\displaystyle \Delta H_{rxn} = \frac{q_{reaction}}{\text{mol of limiting reactant}}$, usually in kJ/mol.
- Phase changes: temperature stays constant while energy goes into breaking intermolecular attractions. $q = n\Delta H_{fus}$ or $n\Delta H_{vap}$.
Bond enthalpies
$\displaystyle \Delta H \approx \sum(\text{bonds broken}) - \sum(\text{bonds formed})$
- Breaking bonds absorbs energy; forming bonds releases energy.
Enthalpy of formation and Hess's law
- $\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_f(\text{products}) - \sum \Delta H^\circ_f(\text{reactants})$. Elements in their standard state have $\Delta H^\circ_f = 0$.
- Hess's law: if you reverse a reaction, change the sign of $\Delta H$. If you multiply a reaction by $n$, multiply $\Delta H$ by $n$. Add steps to get the target reaction.
Topics in this unit
Each topic has its own short notes and practice.
Practice
Heat is released into the surroundings.
$q = 50.0(4.18)(10.0) = 2{,}090$ J.
Phase changes change potential energy, not temperature.
Energy must be added to separate bonded atoms.
Reverse (change sign) and double.
$\mathrm{O_2}$ gas is oxygen's standard state.
$1500 - 1800 = -300$ kJ, so it's exothermic.
The reaction released what the solution absorbed.
Free response
Write your answer first, then open the scoring guide.
Free-response question
A student dissolves 0.0500 mol of $\mathrm{NH_4NO_3}$ in 100.0 g of water. The temperature drops from 22.0 °C to 18.8 °C. Assume the solution's specific heat is 4.18 J/g·°C and its mass is about 104 g.
(a) Is the dissolving endothermic or exothermic? Explain.
Show the answer and scoring guide
Endothermic. The water got colder, meaning the process absorbed heat from the water.
Check off the points you earned:
(b) Calculate the heat absorbed by the process.
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$q_{solution} = 104(4.18)(-3.2) = -1{,}391$ J. The process absorbed about 1.39 kJ.
Check off the points you earned:
(c) Calculate $\Delta H_{soln}$ in kJ/mol.
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$\displaystyle \frac{+1.39\text{ kJ}}{0.0500\text{ mol}} = +27.8$ kJ/mol.
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