AP Chemistry

Unit 7

Equilibrium

12 topics · 44 practice questions · Free response

Notes

Dynamic equilibrium

At equilibrium, the forward and reverse rates are equal, so concentrations stay constant (not necessarily equal). Reactions still happen in both directions.

The equilibrium constant

For $aA + bB \rightleftharpoons cC + dD$:

$$K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}$$
  • Leave out pure solids and liquids. $K_p$ uses partial pressures.
  • $K \gg 1$: products favored. $K \ll 1$: reactants favored.
  • Reverse the reaction: $\displaystyle K' = \frac{1}{K}$. Multiply by $n$: $K' = K^n$. Add reactions: multiply the $K$ values.

The reaction quotient $Q$

$Q$ has the same form as $K$ but uses current concentrations.

  • $Q < K$: the reaction shifts right (toward products).
  • $Q > K$: it shifts left.
  • $Q = K$: at equilibrium.

ICE tables

Set up Initial, Change and Equilibrium rows. Use the changes from stoichiometry and solve for $x$. If $K$ is very small, you can often assume $x$ is negligible compared with the initial value.

Le Châtelier's principle

A system at equilibrium shifts to partly counteract a stress.

  • Add reactant or remove product: shift right.
  • Increase pressure by decreasing volume: shift toward fewer moles of gas.
  • Raise temperature: shift in the endothermic direction. Only temperature changes the value of $K$.
  • Adding a catalyst or an inert gas at constant volume: no shift.

Solubility

$K_{sp}$ for $AgCl(s) \rightleftharpoons Ag^+ + Cl^-$ is $[Ag^+][Cl^-] = s^2$. A common ion lowers solubility.

Topics in this unit

Each topic has its own short notes and practice.

Practice

At equilibrium:
What is the $K_c$ expression for $CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)$?
If $Q = 0.5$ and $K = 2.0$, the reaction will:
For $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$, decreasing the volume shifts the equilibrium:
For an exothermic reaction, raising the temperature:
If $K = 4.0$ for $A \rightleftharpoons B$, what is $K$ for $2B \rightleftharpoons 2A$?
$K_{sp}$ for AgCl is $1.8 \times 10^{-10}$. What is its molar solubility?
Adding NaCl to a saturated AgCl solution will:

Free response

Write your answer first, then open the scoring guide.

Free-response question

$H_2(g) + I_2(g) \rightleftharpoons 2HI(g)$ has $K_c = 49$ at a certain temperature. 1.00 mol of $\mathrm{H_2}$ and 1.00 mol of $\mathrm{I_2}$ are placed in a 1.00 L flask.

(a) Write the $K_c$ expression.

Show the answer and scoring guide

$\displaystyle K_c = \frac{[HI]^2}{[H_2][I_2]}$.

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(b) Calculate the equilibrium concentration of HI.

Show the answer and scoring guide

ICE: $[H_2] = [I_2] = 1.00 - x$, $[HI] = 2x$. $\displaystyle \frac{(2x)^2}{(1.00 - x)^2} = 49 \Rightarrow \frac{2x}{1.00 - x} = 7 \Rightarrow x = \frac{7}{9} = 0.778$. $[HI] = 1.56$ M.

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(c) More $\mathrm{H_2}$ is added after equilibrium. Explain the effect on [HI] using $Q$.

Show the answer and scoring guide

Adding $\mathrm{H_2}$ increases the denominator, so $Q < K$. The reaction shifts right, and [HI] increases.

Check off the points you earned: