AP Chemistry

Unit 6

Thermochemistry

9 topics · 35 practice questions · Free response

Notes

Endothermic and exothermic

  • Exothermic: releases heat to the surroundings; $\Delta H < 0$; the surroundings get warmer.
  • Endothermic: absorbs heat; $\Delta H > 0$; the surroundings get colder.
  • Energy diagrams: products lower than reactants means exothermic.
  • Thermal equilibrium: heat flows from hot to cold until temperatures match. The heat lost by one object equals the heat gained by the other.

Calorimetry

$q = mc\Delta T$, where $c$ is specific heat (water: 4.18 J/g·°C).

  • In a coffee-cup calorimeter, $q_{reaction} = -q_{solution}$.
  • $\displaystyle \Delta H_{rxn} = \frac{q_{reaction}}{\text{mol of limiting reactant}}$, usually in kJ/mol.
  • Phase changes: temperature stays constant while energy goes into breaking intermolecular attractions. $q = n\Delta H_{fus}$ or $n\Delta H_{vap}$.
Heat addedTemperatureMeltingBoilingSolidLiquidGas
During melting and boiling, added heat changes the phase, not the temperature.

Bond enthalpies

$\displaystyle \Delta H \approx \sum(\text{bonds broken}) - \sum(\text{bonds formed})$

  • Breaking bonds absorbs energy; forming bonds releases energy.

Enthalpy of formation and Hess's law

  • $\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_f(\text{products}) - \sum \Delta H^\circ_f(\text{reactants})$. Elements in their standard state have $\Delta H^\circ_f = 0$.
  • Hess's law: if you reverse a reaction, change the sign of $\Delta H$. If you multiply a reaction by $n$, multiply $\Delta H$ by $n$. Add steps to get the target reaction.

Topics in this unit

Each topic has its own short notes and practice.

Practice

When an exothermic reaction happens in water, the water's temperature:
How much heat is needed to warm 50.0 g of water by 10.0 °C?
During boiling, the temperature of water stays at 100 °C because the energy:
Breaking bonds:
If $A \rightarrow B$ has $\Delta H = -50$ kJ, what is $\Delta H$ for $2B \rightarrow 2A$?
Which has $\Delta H^\circ_f = 0$?
A reaction breaks bonds totaling 1,500 kJ and forms bonds totaling 1,800 kJ. What is $\Delta H$?
In a coffee-cup calorimeter, the solution absorbs 3.0 kJ. What is $q$ for the reaction?

Free response

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Free-response question

A student dissolves 0.0500 mol of $\mathrm{NH_4NO_3}$ in 100.0 g of water. The temperature drops from 22.0 °C to 18.8 °C. Assume the solution's specific heat is 4.18 J/g·°C and its mass is about 104 g.

(a) Is the dissolving endothermic or exothermic? Explain.

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Endothermic. The water got colder, meaning the process absorbed heat from the water.

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(b) Calculate the heat absorbed by the process.

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$q_{solution} = 104(4.18)(-3.2) = -1{,}391$ J. The process absorbed about 1.39 kJ.

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(c) Calculate $\Delta H_{soln}$ in kJ/mol.

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$\displaystyle \frac{+1.39\text{ kJ}}{0.0500\text{ mol}} = +27.8$ kJ/mol.

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