Notes
Periodic functions and the unit circle
A periodic function repeats: $f(x + P) = f(x)$ for period $P$.
- An angle in radians is arc length divided by radius. $180° = \pi$ radians.
- On the unit circle, the point at angle $\theta$ is $(\cos\theta, \sin\theta)$, and $\displaystyle \tan\theta = \frac{\sin\theta}{\cos\theta}$.
| Angle | $0$ | $\frac{\pi}{6}$ | $\frac{\pi}{4}$ | $\frac{\pi}{3}$ | $\frac{\pi}{2}$ |
|---|---|---|---|---|---|
| $\sin$ | $0$ | $\displaystyle \frac{1}{2}$ | $\displaystyle \frac{\sqrt2}{2}$ | $\displaystyle \frac{\sqrt3}{2}$ | $1$ |
| $\cos$ | $1$ | $\displaystyle \frac{\sqrt3}{2}$ | $\displaystyle \frac{\sqrt2}{2}$ | $\displaystyle \frac{1}{2}$ | $0$ |
Sinusoidal functions
$f(\theta) = a\sin(b(\theta + c)) + d$
- Amplitude $|a|$, period $\displaystyle \frac{2\pi}{|b|}$, midline $y = d$, phase shift $-c$.
- Modeling: amplitude is half of (max − min); midline is the average of max and min.
Tangent and inverse trig
- $\tan\theta$ has period $\pi$ and vertical asymptotes where $\cos\theta = 0$, like $\displaystyle \theta = \frac{\pi}{2}$.
- $\sin^{-1}$ has outputs in $\displaystyle \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$, $\cos^{-1}$ in $[0, \pi]$, $\tan^{-1}$ in $\displaystyle \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$.
Identities and other trig functions
- Pythagorean: $\sin^2\theta + \cos^2\theta = 1$.
- Sum: $\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta$. Double angle: $\sin 2\theta = 2\sin\theta\cos\theta$.
- $\displaystyle \csc\theta = \frac{1}{\sin\theta}$, $\displaystyle \sec\theta = \frac{1}{\cos\theta}$, $\displaystyle \cot\theta = \frac{1}{\tan\theta}$.
Polar coordinates
A point $(r, \theta)$ is $r$ units from the origin at angle $\theta$. Convert with $x = r\cos\theta$, $y = r\sin\theta$, $r^2 = x^2 + y^2$.
- In a polar graph $r = f(\theta)$, when $r$ is positive and increasing, the point is moving away from the origin.
Topics in this unit
Each topic has its own short notes and practice.
- 3.1Periodic Phenomena
- 3.2Sine, Cosine, and Tangent
- 3.3Sine and Cosine Function Values
- 3.4Sine and Cosine Function Graphs
- 3.5Sinusoidal Functions
- 3.6Sinusoidal Function Transformations
- 3.7Sinusoidal Function Context and Data Modeling
- 3.8The Tangent Function
- 3.9Inverse Trigonometric Functions
- 3.10Trigonometric Equations and Inequalities
- 3.11The Secant, Cosecant, and Cotangent Functions
- 3.12Equivalent Representations of Trigonometric Functions
- 3.13Trigonometry and Polar Coordinates
- 3.14Polar Function Graphs
- 3.15Rates of Change in Polar Functions
Practice
Period $\displaystyle = \frac{2\pi}{4} = \frac{\pi}{2}$.
$\displaystyle \frac{2\pi}{3}$ is in Quadrant II with reference angle $\displaystyle \frac{\pi}{3}$, so cosine is $\displaystyle -\frac{1}{2}$.
Midline $\displaystyle = \frac{40 + 4}{2} = 22$; amplitude $\displaystyle = \frac{40 - 4}{2} = 18$.
Inverse sine outputs are in $\displaystyle \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$, and $\displaystyle \sin\left(-\frac{\pi}{6}\right) = -\frac{1}{2}$.
$\displaystyle \tan x = \frac{\sin x}{\cos x}$ is undefined where $\cos x = 0$.
$\displaystyle \cos^2\theta = 1 - \frac{9}{25} = \frac{16}{25}$, and cosine is negative in Quadrant II.
$\displaystyle x = 4\cos\frac{\pi}{3} = 2$ and $\displaystyle y = 4\sin\frac{\pi}{3} = 2\sqrt3$.
$\cos\theta$ decreases from 1 to $-1$ on $(0, \pi)$, so $r$ decreases from 3 to 1 while staying positive.
Free response
Write your answer first, then open the scoring guide.
Free-response question
The water depth at a dock, in feet, $t$ hours after midnight is modeled by $D(t) = 3\cos\left(\frac{\pi}{6}t\right) + 8$.
(a) Find the maximum depth, the minimum depth and the period.
Show the answer and scoring guide
Maximum $8 + 3 = 11$ ft, minimum $8 - 3 = 5$ ft, period $\displaystyle \frac{2\pi}{\pi/6} = 12$ hours.
Check off the points you earned:
(b) A boat needs at least 9.5 ft of water. Find the first time after midnight when the depth drops to 9.5 ft.
Show the answer and scoring guide
$\displaystyle 3\cos\left(\frac{\pi}{6}t\right) + 8 = 9.5 \Rightarrow \cos\left(\frac{\pi}{6}t\right) = 0.5 \Rightarrow \frac{\pi}{6}t = \frac{\pi}{3} \Rightarrow t = 2$. That's 2:00 a.m.
Check off the points you earned:
(c) Is the depth increasing or decreasing at $t = 8$? Explain.
Show the answer and scoring guide
Increasing. The minimum is at $t = 6$ and the next maximum is at $t = 12$, so between them the depth rises.
Check off the points you earned: