AP Statistics

Unit 4

Inference for Quantitative Data: Means

10 topics · 38 practice questions · Free response

Notes

Why $t$ instead of $z$

We rarely know $\sigma$, so we estimate it with $s$. The standardized statistic then follows a $t$ distribution with $df = n - 1$. $t$ distributions are symmetric and bell-shaped but have heavier tails than the normal; as $df$ grows they approach the normal.

Conditions for means

  • Random: random sample or random assignment.
  • 10%: $n \le 10\%$ of the population when sampling without replacement.
  • Normal/large sample: $n \ge 30$, or the population is approximately normal, or a graph of the sample shows no strong skew or outliers.

One-sample $t$ procedures

  • Interval: $\displaystyle \bar x \pm t^*\frac{s}{\sqrt n}$.
  • Test: $\displaystyle t = \frac{\bar x - \mu_0}{s/\sqrt n}$, with $df = n - 1$.
  • Paired data (two measurements on the same individual, like before and after): take the differences, then do one-sample $t$ on $\mu_{diff}$.

Two-sample $t$ procedures

For two independent groups:

  • Interval: $\displaystyle (\bar x_1 - \bar x_2) \pm t^*\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}$.
  • Test of $H_0: \mu_1 = \mu_2$: $\displaystyle t = \frac{(\bar x_1 - \bar x_2) - 0}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}}$. Use technology for $df$ (or the conservative smaller $n - 1$).

Topics in this unit

Each topic has its own short notes and practice.

Practice

Compared with the standard normal curve, a $t$ distribution with 5 degrees of freedom has:
A random sample of 16 bags has $\bar x = 50.2$ g and $s = 0.8$ g. What is the standard error of $\bar x$?
Each of 25 students takes a test before and after a tutoring program. Which procedure fits?
A sample of 12 has a dotplot that is strongly skewed with an outlier. Why is a $t$ interval risky?
For a one-sample $t$ interval with $n = 20$, what are the degrees of freedom?
A 95% interval for $\mu_1 - \mu_2$ is $(1.2, 4.8)$ minutes. Which conclusion is supported?
$H_0: \mu = 100$, $H_a: \mu > 100$. The sample gives $t = 2.4$ with $df = 24$. The p-value is about:
Which increases the width of a $t$ interval for $\mu$, all else equal?

Free response

Write your answer first, then open the scoring guide.

Free-response question

A random sample of 36 phone batteries lasted a mean of 18.6 hours with standard deviation 2.4 hours. The maker claims a mean of 20 hours.

(a) Construct a 95% confidence interval for the true mean battery life. ($t^* \approx 2.030$ for $df = 35$.)

Show the answer and scoring guide

One-sample $t$ interval for $\mu$. Random sample, $n = 36 \ge 30$. $\displaystyle 18.6 \pm 2.030\left(\frac{2.4}{6}\right) = 18.6 \pm 0.812$, giving $(17.79, 19.41)$ hours.

Check off the points you earned:

(b) Interpret the interval.

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We are 95% confident that the interval from 17.79 to 19.41 hours captures the true mean battery life of all batteries of this kind.

Check off the points you earned:

(c) Does the interval support the maker's claim? Explain.

Show the answer and scoring guide

No. 20 hours is not in the interval, so 20 is not a plausible value for the true mean; the data suggest the mean is lower.

Check off the points you earned: